how do you do this Geometry Proof??!!! i need help plz!?

Question

given: WYis the altitude of I sosceles Triangel WXZ
Proof: Triangle WZY= TRIANGLE WZY :]
im soo lost pllllsease help

Answer 1

In triangles WXY and WZY:
Angle WXY=Angle WZY,
Angle WYX=Angle WYZ. Therefore Angle XWY=Angle ZWY (If 2 angles are equal, then the 3rd angles are the same)

In these same 2 triangles:
XW = ZW (Isosceles Triangle)
WY = WY (Common)
Angle XWY = Angle ZWY (proven above)

Therefore, the 2 triangles are congruent.

Answer 2

Well, first you will have to restate the problem because it makes no sense the way it is currently stated.
1. If the triangle wxz is isosceles, please tell us which of the two sides of the triangle are equal.
2. If WY is an altitude, then WY perpendicular to XZ. Is XZ intended to be the base and WX and WZ intended to be the two equal sides.
3. Finally you say proove triangle WZY = triangle WZY. Well that's really simple. A basic axiom says that a quantity is equal to itself, so of course triangle WZY is equal to itself. This can not be what you meant.

I, going to guess that you meant: proove triangle WZY congruent to triangle WWX. If so, then
1. WZ = WX {Given}
2. WY=WY (Identity or reflexive or quantity =s itself)
3. WY is an altitude. {Given)
4 therefore WY perpendicular to XZ (Given)
5. Therefore WYZ and WYx are right angles (pependicular definition)
6.Therefore triangles WZY and WXYare right triangles (definition of right triangles).
7. Therefore triangle WZY congruent triangle WXY. ( HL theorem, Right triangles havng hypotenuse and leg of one equal to hypotenuse and leg of other are congruent)

Answer 3

You have to prove similarity between the two right angled triangles you get when you bisect triangle WXZ. Hope you get the answer!