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a) dissolution of aluminium in KOH (aq). It is easier to work this out by assuming that the Al dissolves in water to give Al(OH)3, followed by reaction of this trihydroxide with KOH to give KAl(OH)4.

b) formation of the trioxalate complex, i.e. reaction of KAl(OH)4 with oxalic acid in the presence of excess KOH to give K3Al(C2O4)3.H2O

2007-03-29 03:27:24 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Al^3+ + 4KOH ===> 4K+ + Al(OH)4-

3H2C2O4 + 2KOH + KAl(OH)4 ===> K3Al(C2O4)3 + 3H2O

2007-03-29 04:07:28 · answer #1 · answered by steve_geo1 7 · 0 0

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