sin 165 = sin(180 - 15) = sin 15
sin 15 = sin(30/2) = Sqrt [ (1 - cos(30)) / 2 ]
= Sqrt [ (1 - Sqrt(3)/2 )/2 ]
= Sqrt [ (2 - Sqrt(3))/4 ]
= [Sqrt(2 - Sqrt(3))] / 2
2007-03-29 03:23:00
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answer #1
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answered by snpr1995 3
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Hi,
Using a calculator, sin(165 degrees) = .2588190451.
There are also half-angle formulas you could use to find this.
sin( 1/2A) = + or - sqrt[(1-cosA)/2] Since 165 is half of 330, this would be sin( 165) = + sqrt[(1-cos(330))/2]
The sign is a positive because in the second quadrant where 165 is located, sine is always positive. Cos(330) = sqrt(3)/2 = 1.732/2 = .866, so the formula becomes
sin( 165) = sqrt[(1-.866)/2]
sin( 165) = sqrt[(.134)/2]
sin( 165) = sqrt[.067]
sin(165) = .2588
A third way you could do this is by using the sum formula:
sin(A + B) = sinAcosB + sinBcosA
Since 165 = 45 + 120, this would be:
sin(165)=sin(45 + 120) = sin45cos120 + sin120cos45
sin(165)=sin(45 + 120) = 1/sqrt(2)*(-1/2) + sqrt(3)/2*1/sqrt(2)
sin(165) =1/1.414*(-1/2) + 1.732/2*1/1.414
sin(165)=.7072*-.5+.866*.7072
sin(165)=-.3536+.6124
sin(165)=.2588
That's 3 different ways to get there, depending on what section you might be working in.
I hope that helps!
2007-03-29 10:33:01
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answer #2
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answered by Pi R Squared 7
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165 degrees = 165pi/180 = 33pi/36 = 11pi/12
Note that 165 = 135 + 30, so
sin(165) = sin(135 + 30)
Use the sine addition identity
sin(a + b) = sin(a)cos(b) + sin(b)cos(a).
sin(135 + 30) = sin(135)cos(30) + sin(30)cos(135)
135 = 3pi/4 and 30 = pi/6, so
= sin(3pi/4) cos(pi/6) + sin(pi/6)cos(3pi/4)
= [sqrt(2)/2] [sqrt(3)/2] + (1/2)(-sqrt(2)/2)
= [sqrt(2)sqrt(3)] / 4 - sqrt(2)/4
= sqrt(6)/4 - sqrt(2)/4
= [sqrt(6) - sqrt(2)]/4
2007-03-29 10:18:23
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answer #3
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answered by Puggy 7
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First of all sin165 = sin15 (not -sin15 as suggested).
And you find the exact value of sin15 by using the fact that sin30 = 1/2 and using the double angle formula for sine.
2007-03-29 10:20:40
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answer #4
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answered by mathsmanretired 7
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sin(165) = sin(135 + 30)
You can use sum and difference formulas to solve this.
sin(u + v) = sin(u)cos(v) + cos(u)sin(v)
sin(135 + 30) = sin(135)cos(30) + cos(135)sin(30)
sin(135 + 30) = [sqrt(2)/2][sqrt(3)/2] + [-sqrt(2)/2][1/2]
sin(135 + 30) = [sqrt(2)/4] * [sqrt(3) - 1]
2007-03-29 10:18:22
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answer #5
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answered by Bhajun Singh 4
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Same as sin of 15 deg exept it's negative because it's in the 4th quadrant
2007-03-29 10:16:58
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answer #6
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answered by Jack 2
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0.9977972794
2007-03-29 10:22:45
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answer #7
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answered by MARSHAL 2
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0.25881904510252076234889883762405
2007-03-29 10:15:15
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answer #8
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answered by Fordman 7
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