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A rectangle with length l and width w has diagonals that are 10 cm long. Express the area A of the rectangle as a function of w.

2007-03-29 02:20:28 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

L^2+W^2=10^2
W^2=100-L^2 . . . L^2=100-W^2
W=√(100-L^2) . . . L=√(100-W^2)

A=L*W
A=√(100-W^2)*√(100-L^2)
A=√(100-W^2)*√(100- [ √(100-W^2) ] ^2)

2007-03-29 02:33:54 · answer #1 · answered by firephotodude 3 · 0 0

10² = L² + W²
L² = 10² - W² = (10 - W).(10 + W)
L = √ [(10 - W).(10 + W)]
Area = W.√ [(10 - W).(10 + W)]

2007-03-29 09:58:41 · answer #2 · answered by Como 7 · 0 0

umm, use pathogorean theorem to get length l in term of w, then use the rectangle area formula and there you get the area in tem of w!!! EASY

2007-03-29 09:27:18 · answer #3 · answered by Anonymous · 0 0

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