solve the algebratic equation
2007-03-29 01:26:22 · 4 answers · asked by ? 2 in Science & Mathematics ➔ Mathematics
<_ means less than or equal to
2007-03-29 01:45:27 · update #1
– 3d = 2d + 10
– 3d – 2d = 10
– 5d = 10
– d = 10 /5
– d = 2
d = – 2 --------------(1)
7 d <_ 8 d + 11
7 d – 8 d <_ 11
– d <_ 11
d <_ – 11 ------------(2)
Comparing two values of d
– 11 <_ d <_ – 2
2007-03-29 03:02:18 · answer #1 · answered by Pranil 7 · 0⤊ 0⤋
-3d =2d + 10 adding 2d to each side
-3d-2d = -2d +2d+10
-5d= 10
-5d/-5 = 10 /-5
d=-2
-2 satisfies the other equation
-14<-16+11
-14< -5 true statement
2007-03-29 01:34:31 · answer #2 · answered by borgerm 2 · 2⤊ 0⤋
- 3d = 2d + 10
- 3d - 2d = 2d + 10 - 2d
- 5d = 10
- 5d / - 5 = 10 / - 5
d = - 10/5
d = - 2
- - - - - - - -
7d ≤8d + 11
7d - 7d ≤ 8d + 11 - 7d
0 ≤ d + 11
0 - 11 ≤ d + 11 - 11
- 11 ≤ d
- - - - - - - - - s-
2007-03-29 03:11:11 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
-3d = 2d + 10
-3d - 2d = 10
-5d = 10
d = 10/-5
d = -2
and
7d <_ 8d + 11
7d - 8d <_11
-d <_11
d_> -11
So, {d belongs to R| d _> -11 and d = -2}
::.::
2007-03-30 18:52:22 · answer #4 · answered by aeiou 7 · 0⤊ 0⤋