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2007-03-29 01:03:21 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
6y = 18, then
y = 18/6 = 3
So for 6y to be greater than 18, y must be greater then 3.
eg..
6 * 1=6
6 * 2=12
6 * 3=18
6 * 4=24
6 * 5=30
so for y>3 the exp. 6y>18 ... is true
2007-03-29 01:11:07 · answer #1 · answered by suda m 2 · 0⤊ 0⤋
Well if we equalised the equation-:
6y = 18, then
y = 18/6 = 3
So for 6y to be greater than 18, y must be greater than 3.
i.e. If y = 3.1
6y = (6 x 3.1) = 18.6
(thus proving 6y > 18)
2007-03-29 01:08:16 · answer #2 · answered by Doctor Q 6 · 1⤊ 0⤋
divide 18 by 6 like this 18 divided by 6! simple! keep the inequality sign the same it should be y> 3
2007-03-29 01:08:59 · answer #3 · answered by Curly Girl 3 · 0⤊ 0⤋
6y>18
= 6/6 y > 18/6
=y>3
= s.s={y:y>3, y belong to Q}
2007-03-29 01:13:05 · answer #4 · answered by Anonymous · 0⤊ 0⤋
You divide both sides by positive six
6y/6>18/6
therefore y>3
this means y is always greater than three
NB: just something to remember...if you multiply through by a negative number then the sign must change from > to <
2007-03-29 01:09:34 · answer #5 · answered by Anonymous · 0⤊ 0⤋
6y > 18
6y / 6 > 18 / 6
y > 18 / 6
y > 3
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2007-03-29 03:23:06 · answer #6 · answered by SAMUEL D 7 · 0⤊ 0⤋
y is greater than 4
2007-03-29 01:07:22 · answer #7 · answered by balderarrow 5 · 0⤊ 0⤋