Can someone solve these.......?

Question

1.) Approximate solutions of 2x^2-5x+1=0 to the nearest tenth.





2.) Find the sum and the product of the solutions of 6y^2+8y-7=0....y^2 means y squared




3.) Write an equation in standard form with solutions 3+the square root of 2 and 3 minus the square root of negative two...

Answer 1

For the first you merely need to factor. This is made more difficult by the 2 times x squared, but it can be done. You know that both solutions have to carry a minus sign, and they must ad up to -5. One must be 2x - ?, the other x - ?.

In the second, you have to factor as well, in order to get two different expressions to work with.

In the third, you need to work backwards, ie multiply your solutions.

I am not giving you the final answers, not because I cannot, but because I believe you are really asking for assistance.

Answer 2

Do you know the quadratic formula? Use it. Or complete the square which is really the same thing. For example, problem #2 has solutions equal to { -8 ± Sq Root ( 64 + 168 ) } ÷ 12.

Answer 3

3. )
(a - 3-2^0.5)*(a - 3+2^0.5) = 0 is not standard form?

a^2 -6a + 9 -2 = a^2 - 6a +7 = 0 is standard form?

Answer 4

1) the roots are (5 +/- (25-8) ^0.5)/4
roots2.3 and 0.2

2 ) sum =-b/a = -8/6 = -4/3
product = c/a = -7/6

3)( x-3-2^0.5) (x-3+2^0.5)
2^0.5 =1.41
result (x-4.41) (x-0.59) = x^2 -5x +2.6 =0