An object starts at time t = 0 with a velocity of v0 = +50 m/s and undergoes a constant acceleration of a = -1

Question

a) At what time does the speed of the object reach zero?

t1= ___?__

Answer 1

Usually with problems like these it helps to draw the picture but since I can not draw it here and explain it i will just do the calculuations.

Known
V0 = 50m/s
t0 = 0s (I am assuming the units)
a = -1m/s^2 ( I am assuming the units)
v1 = 0m/s (It's in the question when will the object reach zero

Unknown
t1 = ?

How can we relate the t1 with rest of the data.
Use kinematic equation
v1 = v0 + a(t1 - t0)
lets get t1 by it self, to do this first subtract v0 from both sides
v1 - v0 = a(t1 - t0) now divide both sides by a
(v1 - v0)/a = (t1 - t0) now add t0 to both sides
[(v1 - v0)/a] + t0 = t1
So now let's plug and chug.
t1 = [(0 - 50)/-1] + 0
t1 = -50/-1
****Notice if you had kept the units m/s divided by m/s^2 leave you with just s.
t1 = 50sec


If you need further explanation or more help email me or im me. Good Luck.

Answer 2

v = u + at is the formula for this. u is the initial velocity, a is the acceleration, t is the time and v is the final velocity after t seconds.

In our case we have u = 50 m/s a = -1 m/s^2 and v = 0 (it comes to rest) and we need to find t.

0 = 50 - 1. t or 50 - t = 50 and t = 50 seconds.

Answer 3

U can use the formulation v=v0+at ................a million a=acceleration by way of the indisputable fact that's retardind use the formulation v=v0-at......................2 only positioned the values v=0 v0=50 a=11 for............2 and -11 for...............a million ans. = 50/11 for second area use the formulation 2as=(v)2-(v0)2 2x(-11)xs= (50x50)-0

Answer 4

Jesus, you need math for that? My brain spit out 50 seconds by simple reasoning.

Do your own homework. For the time it took you to post this question, you would have figured it out if you tried.

Answer 5

the answer to ur first question is 50 sec
[reason:v=u+at
here v=0,u=50m/sec,a=-1.substituting these values,we get,t=50 sec]
i didn't get ur second part of the question.please be a bit clear!