2007-03-28 18:13:07 · 7 answers · asked by colton c 1 in Science & Mathematics ➔ Mathematics
√48 = √(16•3) = √16 • √3 = 4√3
2007-03-28 18:17:19 · answer #1 · answered by Philo 7 · 0⤊ 0⤋
â48 = â(2^4 *â3) = 2² â3= 4â3
48|2
24|2
12|2
06|2
03|3
01
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2007-03-29 01:38:57 · answer #2 · answered by aeiou 7 · 0⤊ 0⤋
Break 48 into its prime number components:
2*2*2*2*3
To take the square root, take one of each "pair." There are 2 sets of "2" in this example, so you multiply one from each pair. Move the product to the outside of the square root. So, the simplified version of this would be 4*sqrt3
2007-03-29 01:21:22 · answer #3 · answered by Jenn G 2 · 0⤊ 0⤋
In order to simplify radicals, you need to find some square numbers that is a factor of 48.
i.e. 1,4,9,16...
Now, 16 goes into 48, 3 times
So, (sqrt of 16) * (sqrt of 3) = sqrt of 48
You can simplify sqrt of 16 into 4.
The answer is...
4(sqrt 3)
2007-03-29 01:18:38 · answer #4 · answered by Jae 3 · 0⤊ 0⤋
sqrt of 48= sqrt of 16 x sqrt of 3= 4 x sqrt of 3
2007-03-29 02:24:19 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
factrorize 48 = 2^4*3
whcih ever appears twice take ones 2^4 is 2 appearing 4 times take 2*2
which is once cannot be find sqrt rational so sqrt(3)
so we have 4 sqrt(3)
2007-03-29 01:21:04 · answer #6 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
â48=â(2*2*2*2*3)=â(2*2) * â(2*2) *â3=+-{2*2*â3}=+-4â3
2007-03-29 01:18:20 · answer #7 · answered by Daredevil 2 · 0⤊ 0⤋