Balancing Equations can someone check my answers please?

Question

2Fe + 3S = 2Fe2S3

4P4 + 1H2= PH3

2NO+ Cl2 = NOCl

Can someone please correct me and tell me what im doing wrong and how i can fix it for tommorows test thank you

Answer 1

Everything you listed is incorrect. You must have the same number of an atom on each side. Sometimes you have to multiply one side for this to happen

I'm not sure what products you are trying to make, so I can't tell you the answers

Answer 2

First one, just drop the 2 at the front on the right:
2Fe + 3S -> Fe2S3

Second one... you have 16 P on the left and 1 on the right, and 2 H on the left and 3 on the right. Start again:
P4 + H2 -> PH3
We have 4 P atoms on the left and only one on the right, so multiply the right by 4:
P4 + H2 -> 4 PH3
Now the P atoms are balanced, but we have 12 H atoms on the right and only 2 on the left, so we have to multiply the left by 6:
P4 + 6 H2 -> 4 PH3

Third one... you have 2 N, O and Cl atoms on the left and one of each on the right, so multiply the right by 2:
2 NO + Cl2 -> 2 NOCl

Answer 3

H202 ---> H2O + O2 (decomposition) KI + Pb(NO3)2 ----> KNO3 + PbI2 (single determination) 2 Na + CuSO4 ----> Na2SO4 + Cu (single determination) Na2CO3 X (circumstances) 10 H20 ----> Na2CO3 +10 H20 (decomposition) 2 Sb + 3 Br2 ----> 2 SbBr3 (synthesis) F2 + 2 NaCl ----> 2 NaF + Cl2 (single determination) Mg(NO3)2 + Na2CO3 ----> MgCO3 + 2 NaNO3 (double repaclment) 2 CaCO3 ----> 2 CaO + 3 CO2 (decomp) CuSO4 + 5 H2O ----> CuSO4 X (circumstances) 5H2O (synthesis) CH4 + 2 O2 ----> 2 CO2 + H2O (synthesis) they are all balanced ok distinctive than i corrected those 2- CaCO3 ----> CaO + CO2 CH4 + 2 O2 ----> CO2 + 2 H2O