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I am trying to figure out how to draw Lewis structures of compounds with metals. For example, Cr2O3. But I cannot figure out how to determine bond order, or number of electron pairs on each atom.

2007-03-28 17:09:01 · 1 answers · asked by John B 1 in Science & Mathematics Chemistry

1 answers

Simple Lewis structures of compounds with metals can not be drawn for a number of reasons but primarily:

1. Compounds with transition and lanthanide metals do not obey the octet rule. If a transition metal is present in a molecule, they often obey 16 electron or 18 electron rules, but these have many exceptions as well.

2. Many metal containing compounds (especially oxides, minerals etc) are "non-molecular" meaning they do not form discrete molecules like water or methane. Rather they form extended networks of atoms bonding in lattices. The example you give is a non-molecular solid.

3. You can still estimate the number of valence electrons in your example. Your chromium is in the (III) oxidation state if you know how to count d electron shells. (the answer is 3 unpaired electrons)

2007-03-29 02:44:48 · answer #1 · answered by DrSean 4 · 0 0

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