need help finding the definite integral of e^x/(sqrt(e^x-1)) on [0, ln3]?

Answer 1

Let u = e^x -1, then du = e^x dx, so you have the following in terms of u:

⌡u^-.5 du = 2 u^.5
= 2 sqrt (e^x - 1) from 0 to ln 3
= 2 [sqrt (e^ln3 - 1) - sqrt (e^0 - 1)
= 2sqrt 2 - 2 sqrt 0 = 2 sqrt 2

Answer 2

2*sqrt(2)

hint:
put [ (e^x) -1] = t

Answer 3

then why no longer me ? The greater the merrier ! .. ? x d(?x) .................... on [ 0, one million ] = ? (?x)² d(?x) ............... on [ 0, one million ] = [ (?x)³ / 3 ] ................. on [ 0, one million ] = (one million/3) [ (?one million)³ - (?0)³ ] = (one million/3) [ one million - 0 ] = one million/3 ..................................... Ans. .........................................

Answer 4

for(i=0 to ln3)
{
.........................;
Y={e to the power x divided by(square root ...)};
.........................;
}