a # greater than 3?
a. 1/10
b. 1/5
c. 1/12
d. 3/5
2007-03-28 16:21:45 · 7 answers · asked by alona p 1 in Science & Mathematics ➔ Mathematics
P(red = 3 and blue = 4, 5, or 6)
= P(red = 3) * P(blue = 4, 5, or 6)
= (1 / 6) * (3 / 6)
= 1/12
which is answer (c).
2007-03-28 16:26:16 · answer #1 · answered by ymail493 5 · 0⤊ 0⤋
The red die has six numbers on it, so the probability that it will show a 3 is one in six or 1/6.
The blue die also has six numbers, so the probablility it has a number greater than 3 (4, 5, 6) is 3 of 6 or 1/2.
To find the combined probability, multiply the two.
The probability is 1/12, c.
2007-03-28 23:26:54 · answer #2 · answered by Herbie 2 · 0⤊ 0⤋
a 3 on the red die would be 1/6...the blue die having greater than 3, would be 3/6. 3/6 * 1/6 = c. 1/12
2007-03-28 23:26:17 · answer #3 · answered by Gemma 5 · 0⤊ 0⤋
Chances of the red die showing a 3: 1/6
Chances of the blue die showing >3: 3/6, or 1/2
Chances of both: (1/6) * (1/2) = 1/12
Correct answer: C
2007-03-28 23:26:15 · answer #4 · answered by Bramblyspam 7 · 0⤊ 0⤋
c, 1/12
1/6 probability that red die shows a 3
3/6 probability that blue shows 4,5, or 6
1/6(3/6) = 3/36 = 1/12
2007-03-28 23:31:43 · answer #5 · answered by metalluka 3 · 0⤊ 0⤋
c...1/12
probablity of striking 3 is 1/6
probability of striking 4, 5, or 6 is 3/6
Multiply and get 3/36 or 1/12 (c)
2007-03-28 23:26:59 · answer #6 · answered by Anonymous · 0⤊ 0⤋
1/6 for red, 1/2 for blue, I'll let you combine 'em
2007-03-28 23:26:32 · answer #7 · answered by k_e_p_l_e_r 3 · 0⤊ 0⤋