English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2Ag+ + Cd = 2Ag + Cd2+





Enter a numeric answer only

2007-03-28 16:19:11 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

Calculate the standard free energy change in kJ/mol for the above cell reaction.


Enter a numeric answer only

2007-03-28 16:19:45 · update #1

1 answers

According to http://www.northland.cc.mn.us/Chemistry/standard_reduction_potentials.htm

E0(Ag+/Ag) = + 0.7996 V
E0(Cd++/Cd) = -0.403 V

Thus for the reaction

2Ag+ + Cd<=> 2Ag + Cd(2+)

E0 = E0(Ag+/Ag) - E0(Cd++/Cd) = 0.7996-(-0.403) = +1.2026 V

ΔG0 = -nFE= -2*96485*1.2026 = -232 kJ/mole

2007-03-28 23:32:02 · answer #1 · answered by bellerophon 6 · 0 0

fedest.com, questions and answers