The sides of a triangle are represented by y, (y+21) and (y+24). The perimeter of the triangle is 90.?

Question

How can I prove this is or isnt a right triangle?

Answer 1

you can prove that it's a right triangle if
y^2 + (y+21)^2 = (y+24)^2


perimeter of trinagle = y + (y+21) + (y+24) = 90
3y + 45 = 90
3y = 45 => y=15

15^2 + (15 + 21)^2 = 1521
(15 + 24)^2 = 1521

so pythagore is verified and the triangle is a right triangle

Answer 2

y + y + 21 + y + 24 = 90
3y = 45
y = 15

sides are 15, 36, and 39
this is a right triangle, because
15^2 + 36^2 = 39^2
note that it is a multiple of the 5-12-13 triangle

Answer 3

Perimeter=sum of all sides, so y +(y+21) +(y+24)=90
Solving for y we get 3y+45=90, 3y=45, so y=15. The sides are 15, 15+21=36, 15+24=39.
Using pythagorean theorem to see if a^2 +b^2=c^2. if this is true them it is a right angle. (use a=15, b=36, c=39).

Answer 4

90=y+y+21+y+24

3y+45=90

3y=45

y=15

so the sides are 15, 36, 39

plug in the numbers to the pythagoream theorem

39^2=15^2+36^2

1521=1521

Answer 5

y + (y+21) + (y+24) = 90
3y + 45 = 90
3y = 45
y = 15
y+21 = 36
y+24 = 39

Check whether 15^2 + 36^2 = 39^2

Answer 6

we knw that the longest side must be the hypotenuse which is y+24. now using pythagoras theorem, see if the square each sides adds up to the square of (y+24). if thts so, then u have a right angle triangle.

is ((y+24)^2) = (y^2) +((y+21)^2) ?
expand and simplify.
good nite!!!