foci: (0, -5sqrt6), (0, 5sqrt6)
vertices: (0,-4), (0,4)
2007-03-28 16:07:42 · 2 answers · asked by Joey S 2 in Science & Mathematics ➔ Mathematics
please explain how
2007-03-28 16:21:48 · update #1
and yes i meant hyperbola
2007-03-28 16:22:20 · update #2
A parabola only has one "vertex", and an ellipse doesn't have any. So you must mean a hyperbola. The vertices are on the same vertical line, so the general equation for this hyperbola is (y-y1)²/b² - (x-x1)²/a² = 1.
The center (x1,y1) is going to be in between the two focus points, so that would be (0,0). "b" is going to be the distance between the center and a vertex point, so b² = 16.
The distance from the center to a focus point is √(a²+b²), so (5√(6))² = 25*6=150 = a²+16, and so a² = 134. The final equation is:
y²/16 - x²/134 = 1.
2007-03-28 16:16:17 · answer #1 · answered by Anonymous · 1⤊ 0⤋
You want an ellipse, or hyperbola. I'm guessing you're asking for the hyperbola, so here it is:
y^2/16 - x^2/134=1
2007-03-28 16:14:18 · answer #2 · answered by Jeffrey W 3 · 1⤊ 0⤋