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If I have:

Arithmetic Common
Sequence: Difference: Description of nth term:
4,7,10,13,.... 3 a(n)=4+(n-1) * 3
9,21,33,45,.... 12 a(n)=9+(n-1) * 12
6,13,20,27,.... 7 a(n)=6+(n-1) * 7
?,?,?,? ? a(n)= ?

What Comes next?

Thank you

2007-03-28 15:52:54 · 2 answers · asked by jomar 2 in Science & Mathematics Mathematics

2 answers

I am going to say:

a(n) = 13 + (n-1)*18

If you had your 3 lines in this order:

4,7,10,13,.... 3 a(n)=4+(n-1) * 3
6,13,20,27,.... 7 a(n)=6+(n-1) * 7
9,21,33,45,.... 12 a(n)=9+(n-1) * 12
you would see the pattern emerge between each sequence
The first term is +2 then +3, so I would expect 9+4 = 13 for the first term. And the common difference is +4, then +5, so I would expect 12+6 = 18 for the common difference. So

a(n) = 13 + (n-1)*18 which yields the arithmetic sequence

13, 31, 49, 67, ....

2007-03-28 16:01:37 · answer #1 · answered by Kathleen K 7 · 1 0

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2017-01-05 10:11:19 · answer #2 · answered by bolander 3 · 0 0

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