I am trying to solve the following problems analytically, and for some reason they are about to drive me crazy! Any help will be greatly appreciated!
A.) 10^2x-3=17
B.) e^x+1=10
2007-03-28 15:35:45 · 2 answers · asked by Hailey 1 in Science & Mathematics ➔ Mathematics
A) Not sure if you meant to put 2x-3 in parentheses, but I will show it both ways.
10^2x - 3 = 17
10^2x = 20
log 20 = 2x
x = .5log20
OR
10^(2x-3) = 17
log 17 = 2x-3
(3 + log 17) / 2 = x
In both of the above solutions, log is assumed to be the common log which is base 10.
B) e^x + 1 = 10
e^x = 9
Ln 9 = x
2007-03-28 16:05:39 · answer #1 · answered by Kathleen K 7 · 0⤊ 0⤋
(10^(2x))-3=17
10^(2x)=20
LOG10^(2x)=LOG20
2xLOG10=LOG20
(2x)(1)=LOG20
x=(LOG20)/2
(e^x)+1=10
e^x=9
LNe^x=LN9
xLNe=LN9
(x)(1)=LN9
x=LN9
2007-03-28 22:43:32 · answer #2 · answered by fcas80 7 · 1⤊ 0⤋