natasha has 2.35 in nickles and dimes . if she has 33 coins in all find the number of nickles and dimes
2007-03-28 15:11:58 · 10 answers · asked by ツ 4 in Science & Mathematics ➔ Mathematics
n + d = 33
5n + 10d = $2.35
therefore d = 33-n ,,,and we can substitue now that we know what the value of D is
5n + 10d = 235
5n + 10(33-n) = 235
5n + 330 - 10n = 235
330 - 5n = 235.........ADD 5N TO BOTH SIDES
330 = 235 + 5n.....substract 235 from both (without shouting)
330-235 = 235 - 235 + 5n
5n = 95...divide by 5
5n/5 = 95/5
n = 19 = number of nickles
back to original equation n + d = 33
19 + d = 33...subtract 19 from both sides
19 + d - 19 = 33 - 19
d = 14 = number of dimes
verify
19 nickles (.05) + 14 dimes (.10) ======
.95 + 1.40 = 2.35
on the MONEY ! we did it !
2007-03-28 15:24:39 · answer #1 · answered by tomkat1528 5 · 0⤊ 0⤋
Let d = nickels
33-d = dimes
5d + (33-d) 10 = 235 (in cents)
330 - 5d = 235
d= 19 and there are 14 dimes
2007-03-28 22:17:07 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
33 nickels 165
32 nickels 1 dime 170
31 nickels 2 dimes 175
30 180
29 185
28 190
27 195
26 200
25 205
24 210
23 215
22 220
21 225
20 230
19 nickels 14 dimes 235
2007-03-28 23:17:21 · answer #3 · answered by virgilwatson 2 · 0⤊ 1⤋
23 dimes and 1 nickel
2007-03-28 22:17:38 · answer #4 · answered by anonymous 5 · 0⤊ 1⤋
d + n = 33
.1d + .05n = 2.35
d = 33 - n
.1(33-n) + .05n = 2.35
3.3 - .1n + .05 = 2.35
-.05n = -.95
n = 19
d = 99 - 19 = 14
14 dimes and 19 nickels.
2007-03-28 22:18:22 · answer #5 · answered by 7 · 0⤊ 0⤋
2.35=n*0.05 + d*0.10 eq (1)
33=n+d eq (2)
rearranging eq (2)
n=33-d eq (3)
substuting (3) into (1)
2.35=(33-d)*0.05 + d*0.10 eq (4)
solving (4) for d
2.35=33*0.05 - d*0.05 + d*0.10
2.35-33*0.05 = d*(0.10-0.05)
2.35-1.65 = d*0.05
0.70/0.05=d
14=d
substuting d into (2) and solving for n
33=n+14
33-14=n
19=n
check
19*0.05 + 14*0.10 = ?
0.95 + 1.40 = ?
2.35 = correct
I labeled the eqiations with eq (1), eq(2) ... far to the right, but the spaces aren't displayed correctly
2007-03-28 22:29:29 · answer #6 · answered by Hector R 1 · 0⤊ 0⤋
.05x + .10(33-x) = 2.35
x = # nickles
33-x = # dimes
2007-03-28 22:16:17 · answer #7 · answered by Maverick 7 · 0⤊ 0⤋
19 nickles
14 dimes
n=nickles
d=dimes
n+d=33
d=33-n
.05n + .1d = 2.35
d=23.5-.5n
33-n=23.5 - .5n
n=19
d=33-19
d=14
2007-03-28 22:28:08 · answer #8 · answered by Anonymous · 0⤊ 0⤋
you solve it as a system of equations.
x being the number of nickels and y being the number of dimes
x+y=33
.05x + .10y=2.35
I would use substitution to solve.
2007-03-28 22:18:21 · answer #9 · answered by Math Teacher 3 · 0⤊ 0⤋
what he said
2007-03-28 22:17:55 · answer #10 · answered by dikhead 3 · 0⤊ 0⤋