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Falling objects drop with an average acceleration of 9.8m/sec/sec or 9.8m/sec to second. If an object falls from a tall building, how long will it take before it reaches a speed of 49m/sec? How is that calculated?

2007-03-28 15:03:56 · 2 answers · asked by daydream♥believer 4 in Science & Mathematics Physics

2 answers

v=at
v=49m/s
a=-9.8m/s (pay attention to the negative not neccessarly for this problem, but ones you will do later!)

therefore:
v/a=t
(49m/s) / (-9.8m/s)= -5s well you can't have a negative time, therefore t=5s

2007-03-28 15:53:43 · answer #1 · answered by lifeisgood20 2 · 0 0

v = at (starting from rest)
49 m/s = (9.8 m/s²)t
t = 49 / 9.8 seconds

(neglecting effects of air, of course)

2007-03-28 22:25:49 · answer #2 · answered by CheeseHead 2 · 1 0

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