how do you solve this using system of equations?
Adult tickets are sold for the school musical for $3.50 and student tickets are sold for $2.50 . . . ..321 tickets are sold altogether for 937.50. how many of each ticket were sold?
2007-03-28 14:58:28 · 5 answers · asked by ツ 4 in Science & Mathematics ➔ Mathematics
i dont even know what to say.....i learned this stuff in 3rd grade......
2007-03-28 15:04:17 · answer #1 · answered by person 1 · 0⤊ 2⤋
There are different ways of solving this, but here is how you solve it using a system of equations, which is what you asked for:
If A is the amount of adult tickets sold, and S is the amount of student tickets sold, then we know A+S=321, since there were 321 tickets sold altogether. The adult tickets sold for $3.50 each, so the amount of money from adult ticket sales is 3.50*A. Likewise, the money from all the student tickets was 2.50*S. Add them together, and they're supposed to be 937.50. So 3.5A + 2.5S = 937.5
You now have two equations with two unknowns, so you can use substitution to solve this system of equations for A and S.
2007-03-28 22:07:47 · answer #2 · answered by Anonymous · 0⤊ 0⤋
321 in total
$3.50 Adult
$2.50 Student
Total : $937.50
200 Adult tickets were sold.
$3.50 x 200: $700
95 Student tickets were sold.
$2.50 x 95: $237.5
$700 + $237.5 = $937.50
2007-03-28 22:08:28 · answer #3 · answered by Amna 2 · 0⤊ 0⤋
ok, i have a fairly simple way to solve this and i hope you can follow what i am doing
first-set up 2 equations that are proportional
(x=adult tickets y=student tickets)
x+y=321 (because there are 321 tickets total)
3.50x+2.50y=937.50 (because that is the total cost)
second- make one pair of variables opposites by multiplying throught the whole equation
(x+y=321)x-3.50
-3.5x-3.5y= -1123.5
third- you line up the equations and add them up
-3.5x-3.5y= -1123.5
3.5x+2.5y=937.50
0x-1y= -186 then you solve
y=189 (186 student tickets, 135 adult tickets)
I know that you are probly thinking that i just pulled some of these numbers and equations out of my *** so if you need extra help email me and i can explain better dare_to_take_risks@yahoo.com
2007-03-29 00:29:58 · answer #4 · answered by Jared 2 · 0⤊ 0⤋
Suppose there were x adult tickets. Since there were 321 tickets altogether, there must be (321-x) student tickets.
The total price is then
(3.5)x + (2.5)(321-x) = 937.5
<=> 3.5 x + 802.5 - 2.5 x = 937.5
<=> x = 135
So there were 135 adult tickets and (321-135)=186 student tickets.
2007-03-28 22:03:01 · answer #5 · answered by Scarlet Manuka 7 · 0⤊ 0⤋