Benzene reacts w/ bromine to produce bromobenzene according to the following equation:
C6H6(l) + Br2(l) -----> C6H5Br(l) + HBr(g)
or
Benzene + Bromine -----> Bromobenzene + Hydrogen bromide
A) which is the limiting reagent?
B) How many grams of bromobenzene are formed in the reaction?
I need to know the answer and also how to get it, because i have a few more questions exactly like it.
2007-03-28 14:40:36 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
So i really need the answer and step by step how to do it
2007-03-28 15:10:05 · update #1
Luca, You must give the amounts of each reactant to calculate the limiting reagent.
Note that one mole of benzene will react with one mole of bromine. If you have 0.5 mol of benzene you would need 0.5 mole of Br2. This logic works when the number of moles of each of the reactant is the same when the equation is balanced.
2007-03-28 14:52:43 · answer #1 · answered by docrider28 4 · 0⤊ 0⤋
DUNNO DONT UNDERSTAND THAT OK
LOL
2007-03-28 14:44:12 · answer #2 · answered by Anonymous · 0⤊ 0⤋