he's so not my type, but I think he is so hot.
2007-03-28 14:30:38 · 10 answers · asked by Insert Name Here 1 in Entertainment & Music ➔ Celebrities
You wanna know why you think he's hott and yet he's not your type?
Eddie Izzard is very comfortable with his own sexuality and he literally OOZES confidence about who he is and that is always sexy! He is an extremely funny
comedian (cross dresser that's NOT gay!) and he is also a very good actor.
His new show called The Riches really allows him to showcase his talent as a seasoned actor.
I've always liked this guy, he just has that 'IT' factor!
2007-03-28 15:01:35 · answer #1 · answered by Knuckledragger 4 · 0⤊ 0⤋
Who's Eddie Izzard?
2007-03-28 14:33:39 · answer #2 · answered by Anonymous · 0⤊ 0⤋
that is on easily one of his early excursions, i imagine that is 'Unrepeatable' (if no longer, Definate Article). He talks about Prince Charles making speeches and how he fiddles mutually with his blouse cuffs because he's worried. Eddie thinks he appears like a magician who's about to do a trick and pull a set of plant existence out of his sleeves. I nonetheless love the formerly excursions over some thing extra modern.
2016-12-02 23:09:17 · answer #3 · answered by dismukes 4 · 0⤊ 0⤋
In a weird way, yeah! I think it's his sense of humor and intellect.
2007-03-28 20:00:06 · answer #4 · answered by cavu_13 3 · 0⤊ 0⤋
He's Dress To Kill - yummy!
pun intended ;)
2007-03-28 14:34:05 · answer #5 · answered by Bella-El 6 · 0⤊ 0⤋
I find him much more appealing with make-up, but I know what you mean. Weird, huh?
2007-03-28 14:33:38 · answer #6 · answered by peaceandharmonyandmercy 3 · 0⤊ 1⤋
He kind of is in a way. Ha. I can't explain it..
2007-03-28 14:32:56 · answer #7 · answered by kasey1720 2 · 0⤊ 1⤋
yeah i agree
2007-03-28 14:32:55 · answer #8 · answered by heather s 1 · 0⤊ 1⤋
yes! he rocks. have you watched Riches on FX? it it v. good. :)
2007-03-28 14:33:50 · answer #9 · answered by imnotachickenyoureaturkey 5 · 0⤊ 1⤋
good
2007-03-28 14:33:26 · answer #10 · answered by Anonymous · 0⤊ 1⤋