log [base 7] 1/49 = x
so you want to figure what this equation 7^x = 1/49
x = -2 because 7^2 = 49, but you wnt 1/49, so it would be 7^-2 because the negative says it should be in the denominator.
2007-03-28 14:25:19
·
answer #1
·
answered by cnuswte 4
·
0⤊
0⤋
A log is a missing exponent. So this question is asking 7 to what power yields 1/49. You can create a simple exponential equation and then use common bases:
7 ^x = 1/49
7^x = 7^ -2
x = -2
2007-03-28 14:26:08
·
answer #2
·
answered by Kathleen K 7
·
0⤊
0⤋
The question is asking, "7 to what power is 1/49?"
The answer would be -2, because 7^-2 = 1/7^2 = 1/49.
2007-03-28 14:23:13
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
Simple, simple. I love log manipulation. Recognize that log(a/b) = log a - log b. So log7(1/49) = log7(1) - log7(49). Well, it's obvious log7(49) = 2... and log base ANYTHING of 1 is just 0. So you have 0 - 2, which is just -2.
2007-03-28 14:26:14
·
answer #4
·
answered by dac2chari 3
·
0⤊
0⤋
log sub7 1/49 = log sub7 1 - log sub7 49
=0 - 2
=-2
the answer is probably -2 itself.
2007-03-28 14:25:58
·
answer #5
·
answered by Kuji K 2
·
0⤊
0⤋