2007-03-28 14:03:51 · 6 answers · asked by j b 1 in Science & Mathematics ➔ Mathematics
If the problem is:
x times (5/2) = 243
then divide each side by (5/2)
x = 97.2
If the problem is:
x raised to the (5/2) power = 243
then raise both sides by (2/5)
and x = 9
2007-03-28 14:07:03 · answer #1 · answered by VJ 2 · 0⤊ 0⤋
Raise both sides to the 2/5 power
The 5th root of 243 = 3 since 3^5 = 243
x = 243^2/5 = 3^2 = 9
2007-03-28 14:06:31 · answer #2 · answered by richardwptljc 6 · 0⤊ 0⤋
You raise each side of the equation to the reciprocal power:
x^(5/2) ^ (2/5) = 243 ^(2/5)
x = the fifth root of 243, squared (always remember, a fractional exponent is POWER/ROOT -- do the root first, it makes the numbers smaller right of the bat ). So the 5th root of 243 is 3, then square it --> 3^2 = 9
2007-03-28 14:24:07 · answer #3 · answered by Kathleen K 7 · 0⤊ 0⤋
Divide both sides by 5/2.
x = 243 divided by 5/2
x = 97.2
Guido
2007-03-28 14:18:14 · answer #4 · answered by Anonymous · 0⤊ 0⤋
5/2x = 243
(5/2 )(2/5)x = 243 (2/5)
x = 486/5
2007-03-28 14:08:52 · answer #5 · answered by frank 7 · 0⤊ 0⤋
97 1/5
2007-03-28 14:07:48 · answer #6 · answered by ???? 2 · 0⤊ 1⤋