Math Help Please?

Question

Simplify each radical expression.

( √3 + 5 ) ( √3 – 3 )

so far I have got this far but I don't know if I'm doing this right please help.

( √3 + 5 ) ( √3 – 3 )

√3 * √3 – 5 √3 + 5 √3 – 3

Answer 1

it should be √3 * √3 -3√3 + 5√3 -15
= √9 +2√3 -15
= 3 + 2√3 -15
= 2√3 - 12

basically, use the FOIL method

Answer 2

( √3 + 5 ) ( √3 – 3 )
=
(√3*√3) + (√3 * -3) + (5 * √3) + (5 * -3)
=
3 - 3√3 + 5√3 - 15
=
-12 + 2√3

Answer 3

3+5√3-5√3-15
-12

Answer 4

(√3 + 5) (√3 -3)

√3 x √3 - 3√3 + 5√3 - 15 Note: (√3 x √3 = 3)
3 - 15 + 2√3 Note: -3√3 + 5√3 = √3(-3+5) = √3(2)
-12 + 2√3
2(-6 + √3)

Answer 5

(√3+5)(√3-3)
3-3√3+5√3-15
3+2√3-15
-12+2√3

Answer 6

Your multiplication is sloppy. It's the old FOIL routine.
F sqrt(3) x sqrt(3) = 3
O -3 sqrt(3)
I 5sqrt(3)
L -15
Put it all together now to get - 12 + 2sqrt(3) or
2 ( sqt(3) - 6 )

Answer 7

(sqrt(3) + 5) (sqrt(3) -3)

= sqrt(3) x sqrt(3) +5sqrt(3) -3sqrt(3) -15

= sqrt (9) + 2sqrt(3) -15

= 3 -15 + 2sqrt(3)

= -12 + 2sqrt(3)