Help with math prolbem?

Question

There are 100 baskets. The first bunny takes out every egg. The second bunny puts back in the basket every second egg, the thid one puts back every third egg, and so on. Also, if an egg is in a basket, the bunny puts it back out again. How many eggs are still out of the basket? Help and how to solve it?

Answer 1

Not sure I understand exactly what is happening here!

Start 100 baskets each with 1 egg?
Bunny 1 takes the egg out of every basket?
Bunny 2 "Moves the egg" on every other basket
(places the egg back into the basket!)
Bunny 3 "Moves the egg" on every third basket
(if out he puts back in and if in takes back out?)

And so on means keep going forever?

If all that is correct then it would work as follows!
Say the baskets are numbered 1 to 100

basket 1 is only touched by the 1st bunny
(only one factor of 1) if the number of factors is odd then egg is out! if even then it ended up in the basket

basket 2 is touched by bunny 1 and 2
(factors are 1 and 2, so even is in!)

So find the number of factors of each number for 1 to 100 and count the numbers:
odd= out even = in