A 0.226 g sample of CO2 has a volume of 525 ml and a pressure of 455 mm Hg. What is the temperature of the gas?
note here--PV=nRT
R=0.0821 L atm/mole K
2007-03-28 13:18:29 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
V=525mL= .525L
P=455mmHg*1atm/760mmHg=.599atm
find the mole of Co2
they gave .226g
so .226g*1mole/44.01g= .00514mole CO2.
so PV=nRT
you want to solve T
T=PV/nR =( .599*.525)/(.00514*.0821)= 745.2 K
note you need to put the unit when you calculate T cuz i am lazy to write , i hope you understand it. good luck
2007-03-28 13:29:51 · answer #1 · answered by Helper 6 · 0⤊ 0⤋
This is really simple. All you have to do is get your numbers in the right units, put 'em into the equation you've been given (PV = nRT, the ideal gas law) and solve for T. I really hope you can do that. If you can't, there's no hope for you.
I will help you with the first step - conversions to the right units - but after that you're on your own. Note that according to the periodic table, there are 44 grams in a mole of CO2. (n in the ideal gas law stands for moles.) There are a thousand ml in a liter (that's for volume, V, in the equation) and 760 mmHg, or torr, in an atmosphere (that would be pressure, P).
OK - from here on I bow out. God help you if you can't get this question.
2007-03-28 20:28:49 · answer #2 · answered by dac2chari 3 · 0⤊ 0⤋
PV=nRT so T= PV/nR
P= 455 mm Hg / 760 mm Hg per 1 atm
MW of CO2 = 12 + 2 (16) = 44 g/mole
n = 0.226 g / 44 g/mole
plug in everything in T= PV/nR and you get your answer in Kelvins (K).
2007-03-28 20:30:38 · answer #3 · answered by koons 3 · 0⤊ 0⤋
You can do it using that gas law, but I prefer Avogadro, which I will illustrate: 0.226 grams is 0.226/44 = 5.1364 millimoles. At STP, one millimole fills 22.4 milliliters, so the sample would fill 115.05 ml. At the reduced pressure, it would fill 155.05 x 760/455 milliliters or 192.2 ml. To fill 525 ml, the temperature must be 525/192.2 x 273 K = 745.8K = 472.8 C.
2007-03-28 20:29:50 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Wonder has given you a clue, the tric here is to make sure that all unit selections are consistent which means:
Volume should in litre
Pressure should be in atm ( see how the value of R is expressed )
what proportion is 0.226g of the gram molecular weight of CO2.
T will be in Kelvin.
http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/idegas.html
2007-03-28 20:39:06 · answer #5 · answered by Anonymous · 0⤊ 0⤋
T = PV/nR
2007-03-28 20:23:59 · answer #6 · answered by Wonder 2 · 0⤊ 0⤋