A trains velocity increases from 7m/s to 18m/s over a period of 120s.Caculate its acceleration.
2007-03-28 13:11:21 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Hah, no, not a hard math problem by any count. (Yay for weak puns!) Way to try to get other people to do your math homework for you by challenging them with the ole "this is a very hard problem" ploy. But just because I'm a nice person, I will solve it out of the kindness of my heart. The average acceleration of the train is just its change in velocity over the time it took, or (18 m/s - 7 m/s)/(120 s), which is 0.092 m/s^2. In English, it increases speed by nearly a tenth of a m/s (units of speed) every second.
2007-03-28 13:16:42 · answer #1 · answered by dac2chari 3 · 0⤊ 0⤋
11 m/s / 120 s
LOL!
ok ok - I'll reduce it for you. Your train is accelerating at 0.091666666666666666666666666666667 m / s / s
18m/s - 7m/s = 11m/s (the overall speed increase) divided by the time it took to get there (120 seconds.) The problem as stated IS an equally valid answer (11/m/s/120 s,) but that's not what your teacher wants.
2007-03-28 20:19:16 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Given variables: velocity (V), acceleration (A), and time (T)
Given formula for calculating average acceleration:
A (average) = [V - Vo] / T
*Variable definitions and formula given by website under Source(s) below. The diagram in the website illustrates that Vo is the starting or intiial velocity.
Substituting the numerical values given in the problem:
A (average) = [18 - 7] / 120 = 11 / 120 = .0916 meters per second squared.
2007-03-28 20:26:28 · answer #3 · answered by Piguy 4 · 0⤊ 0⤋
acceleration is speed/time so u find the difference in speeds by subtracting the 7 m/s from 18 m/s which is 11m/s. Then u divide that by the time interval which is 120 s so the acceleration is 0.092 m/s squared!
2007-03-28 20:22:48 · answer #4 · answered by shevonne 2 · 0⤊ 0⤋
This is physics not math. Vfinal=Vinitial+at
so.
18=7+a(120)
Minus the 7.
9=a120
Divide 9 by 120.
.075m/s^2=a
2007-03-28 20:18:34 · answer #5 · answered by b_ridge_it122 2 · 0⤊ 1⤋
Acceleration =
Final Velocity - Initial Velocity
divided by time
(18 m/s) - (7 m/s)
------------------------ =
120 s
11 m/s
----------- = (approx.) 0.092 m/s^2
120 s
2007-03-28 20:21:56 · answer #6 · answered by VJ 2 · 0⤊ 0⤋
(18 - 7 ) / 120 = 0.09166666 m / s^2
2007-03-28 20:18:28 · answer #7 · answered by hustolemyname 6 · 0⤊ 0⤋