A 92 kg astronaut and a 1600 kg satellite are at rest relative to the space shuttle. The astronaut pushes on the satellite, giving it a speed of 0.16 m/s directly away from the shuttle. Seven-and-a-half seconds later the astronaut comes into contact with the shuttle. What was the initial distance from the shuttle to the astronaut?
2007-03-28 12:42:58 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
his speed must be 1600 / 92 * 0.16 m/s = 2.7826 m/s
in 7.5 seconds he travels20.87 m which was the initial distance
2007-03-28 12:52:21 · answer #1 · answered by hustolemyname 6 · 0⤊ 0⤋
Let me show you how hustolem… got the answer.
Conservation of momentum.
Momentum before = Momentum after
M*u1 + m*u2 = M*v1 + m*v2
0 + 0 = 1600 kg*0.16 m/s + 92 kg*v2
Solve for v2
2007-03-28 20:51:14 · answer #2 · answered by sojsail 7 · 0⤊ 0⤋