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here's the question:
-2x+y=1
-4x+2y=-8

i need a step by step solution
thank you!

2007-03-28 12:37:31 · 5 answers · asked by mikage2590 1 in Education & Reference Homework Help

5 answers

-2x+y=1
Isolate Y ->

Y=2x+1

-4x+2y= -8
Isolate Y ->
2y=4x-8
Remove Coefficient ->
y=2x-4

In this form, called 'slope intercept' y=mx+b m= slope
IN both lines m=2, and when two lines have the same slope they are parallel. The definition graphically of a system of equations is all points on the graph where the equations graphs intercept. When two lines are parallel they do not intercept, therefore there are no solutions to the system of equations.

2007-03-29 00:26:54 · answer #1 · answered by thewiseman2008 3 · 0 0

Multiply the top equ by 2:

2(-2x+y)=2(1)
-4x+2y=-8

-4x+2y=2
-4x+2y=-8

Since the x and y coeffs are the same, they have the same slope, since the constant is different, the lines are parallel, and there are 0 solutions.

2007-03-28 19:43:40 · answer #2 · answered by JD H 2 · 0 0

y=2x+1 would be your first formula but converted to slope intercept format you get this bu moving theses variables to the other side so to to do that u have to change the sign of the slope and y intercepts in this example and the second formula would be
2y=4x+8
-2 -2
the twos cancel out an it makes y=4x+6
plot the y intercepts in both equations which are 6 and 8 that use the formulas slop to create a line........

2007-03-28 19:53:28 · answer #3 · answered by lilmisssatisfy 1 · 0 0

You have 2 lines that you can draw on a graph:

y = 2x + 1
divide the 2nd one by 2, so y = 2x - 4

For y = y, 2x + 1 = 2x - 4

There is no solution, since the lines are parallel.

2007-03-28 19:44:22 · answer #4 · answered by Anonymous · 0 0

one solution, the lines intersect in only one place

2007-03-28 19:43:06 · answer #5 · answered by 1234abcd 2 · 0 0

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