Help please Solve each system by substitution?

Question

5x - 2y = -5
y - 5x = 3

Answer 1

5x-2y=-5
y-5x=3 which is also y=3+5x

Substitute y with 3+5x in the 5x+2y=-5 and distribute to solve for x:
5x-2(3+5x)=-5
5x-6+10x=-5
x=-1/5

Then substitute x in the y-5x=3 and distribute and solve for y:
y-5(-1/5)=3
y=2

Answer 2

y=3+5x
5x-2(3+5x)= -5
5x-6-10x= -5
-5x-6= -5
-5x=1
x= -1/5

y-5(-1/5)=3
y+1=3
y=2

Answer 3

y=5x+3
5x-2(5x+3)=-5
5x-10x-6=-5
-5x-6=-5
-5x-6+6=-5+6
-5x=1
-5x/-5=1/-5
x=-1/5

y-5(-1/5)=3
y+1=3
y+1-1=3-1
y=2