Well I'm no expert on physics but using logic I would say that it's because of the buoyancy factor. The buoyancy of water acts against the force of the weight of the object, therefore if you were holding the object under water you couldn't have to use as much force because the water is doing some of it for you. It obviously doesn't actually lose weight, it just seems like it.
Technical explanation: The net upward buoyancy force is equal to the magnitude of the weight of fluid displaced by the body.
This enables the object to float or at least seem lighter.
2007-03-28 12:25:41
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answer #1
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answered by x_just_imagine 2
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It has to do with the relative density of the objects. The closer the density of the object relative to water, the more the object will seem weightless. If there's a large difference in density between the object and water, the less it will seem to be weightless. This will work both for objects less dense than water and objects heavier than water. If an object is less dense than water, it is said to be buoyant. The reason for this is the displacement of water with respect to the object. Density is defined as the mass per unit volume.
2007-03-28 12:56:13
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answer #2
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answered by misoma5 7
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Buoyancy. The water closer the the surface of the water is at a lower pressure than that below it. The pressure difference creates an upward force on anything in the fluid, which (partially or completely) cancels out the downward gravitational force.
2007-03-28 12:28:30
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answer #3
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answered by OpNickC 3
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When an object is immersed in water, it displaces a volume of water (x.) The mass of that water is based on the volume of displacement - 8.33 lbs/gallon, I believe. The force of buoyancy - the amount of weight you appear to lose from the object - is equal to the mass of the displaced fluid.
2007-03-28 12:26:55
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answer #4
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answered by Anonymous
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Like, for instance, Rosie O' Donnell?
Don't know, sorry.
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2007-03-28 12:28:34
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answer #5
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answered by Anonymous
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