Calculate mass of AgCl formed when 0.250L of 0.100M solution of NaCl is added to 0.100L of a 0.200M AgNO3?

Question

What is the limiting reactant

given AgNO3 + NaCl= AgCl+ NaNO3

Thats why i asked this question.so i can figure out how to do it and be able to do the other 20 problems i have on my homework.but right now,i dont know how to do this.

Answer 1

Here are the steps. You can do the math

You need to calculate the moles of NaCl that you have. A 1.0 molar solution has 1 mole in 1 liter. You are starting with 0.1 Molar and only 0.25 liters. Multiply them correctly and you get moles of NaCl.

Now multiply by the molar ratio. This one is simple, it is 1:1.

This gives you moles of AgCl. Multiply by the molecular mass of AgCl and you get the grams of AgCl.

Now repeat the whole process for calculating the moles of AgNO3.

The reactant which calulates to the least amount of AgCl is the limiting reactant

Answer 2

You will never pass this class if you don't do your own homework.