I need to find out a distance of a triangle side?

Question

I AM BUILDING A RING FOR DOGS TO COMPETE IN AND I NEED IT TO BE SQUARE.THE RING IS 100FT SQUARE SO I NEED TO KNOW THE DISTANCE FROM FAR CORNER TO FAR CORNER

Answer 1

If the AREA of the ring is 100 square feet, and it's shape is square, then each side is 10 feet in length.

Therefore the diagonal is:
= SQRT (Side 1 * Side 1 + Side 2 * Side 2)
= SQRT (10*10 + 10*10)
= SQRT (200)
= 14.14 feet = 14 feet 1.68 inches

If what you mean is each SIDE is 100 feet in length,
the diagonal becomes:
SQRT (100*100 + 100*100)
= SQRT (20000)
= 141.42 feet = 141 feet 5.05 inches

Answer 2

a2+b2 = c2, pythagore, right, the a and b are normal sides, the c side is the longest one , like if you draw a line from corner to corner in a square; this is the side you're looking for. The formula just rearranged tells you that c (not squared) is equal to the square root of (a2+b2),
in this case c this long side = the square root of (100 suared + 100 squared);

c= square root of (10 000 + 10 000)
= square root of (20 000)
= 141.42 ft
= 141 feet, 5 inches (almost 5.1 in actually)

141' 5'' is the measurement of that distance from far corner to far corner of your 100 sq. ft ring. Good luck. Measure it to be sure when you are done making the ring.

Careful, like Can Texan said, that s the length of your long side if your other sides are 100 feet long each.

If they are only 10 feet long each, then 14.14 inches.

Answer 3

Do you mean that the "ring" is a square, with each side 100 feet long?

Then the diagonal is mathematically 141 feet, 5.1 inches. But that's only if you can build it almost exactly square, with 90.00 degree right angles. Yours could be off by an inch or more.

Answer 4

The length of the hypotenuse of a right triangle can be found using the Pythagorean theorem a^2+b^2 = c^2.

100^2+100^2 = 20000

The square root of 20000 =141.42135623730950488016887242097

Answer 5

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i seriously don't get your question =(