21x + 28 = 16x + 40 + 13
21x + 28 = 16x + 53
5x = 25
x = 5
2007-03-28 08:40:14
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answer #1
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answered by bigbit22 3
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X=5
2007-03-28 08:41:13
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answer #2
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answered by cooldudeanush 2
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7(3x + 4) = 8(2x + 5) + 13
21x+28=16x+40+13
21x+28=16x+53
5x+28=53
5x=25
x=5
2007-03-28 08:48:48
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answer #3
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answered by gerbilcg05 1
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7*3x + 7*4 8*2x + 8*5
21x + 28 16x + 40 + 13
blah blah wateva they said x=5
2007-03-28 08:45:52
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answer #4
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answered by ♫♥~nycgirl~♥♫ 5
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what's this? Your son's homework? lol...in simple terms kidding. I won't provide away the respond so as which you will want a minimum of somewhat of a undertaking. besides, so a procedures you're good. After that, you combine like words. via fact the only like words are the 40 and the 13 that are on the remarkable area of the =, you upload them. Then, you subtract 16x from the two facets, leaving you with 2 numbers on the left and one on the remarkable. Subtract the 28 from the two facets now and you have (a quantity) circumstances (x) on the left and (a quantity) on the remarkable. Divide the two facets via the coefficient (the quantity till now the x) and you have your answer. stable success!
2016-11-24 19:49:33
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answer #5
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answered by tehney 4
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x=5.
2007-03-28 08:44:06
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answer #6
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answered by Anonymous
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7(3x + 4) = 8(2x + 5) + 13
or, 21x + 28 = 16x + 40 + 13
or, 21x - 16x = 40 +13 - 28
or, 5x = 25
or, x = 25/5
or x = 5
Just copy this in ur maths copy
2007-03-28 08:46:54
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answer #7
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answered by Periscope 2
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multiply out everything
21x + 28 = 16x + 40 + 13
21x + 28 = 16x + 53
21x - 16x = 53 - 28
5x = 25
x = 5
2007-03-28 08:41:33
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answer #8
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answered by heavenly_97 2
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