__ K2Cr2O7 + __ C2H6O + __ H2SO4 >>> __ Cr2(SO4)3 +__ K2SO4 + __C2H4O2 + ___ H2O
That is the equation. I havent been able to get his for a couple weeks and it is really starting to bug me. I hope you can read it. The bigger numbers are the subscripts. I hope this does not make it to confusing. Thanks You SOOO much!
2007-03-28 07:48:53 · 3 answers · asked by Amanda A 2 in Science & Mathematics ➔ Chemistry
(Cr2O72- +14H+ +6e->>2Cr3+ +7H2O)2
(C2H6O + H2O >> C2H4O2 + 4H+ + 4e-)3
2Cr2O72- + 28H+ + 12e- >> 4Cr3+ + 14H2O
3C2H6O + 3H2O>>3C2H4O2 + 12H+ + 12e-
______________ ___ ____ _____ _________
2Cr2O72- + 3C2 H6O + 16H+ >>4Cr3+ +3C2H4O2+11H2O
2K2Cr2O7+3C2H6O+8H2SO4 >2Cr2(SO4)3+
2K2SO4 + 3C2H4O2 +11H2O
2007-03-28 08:06:32 · answer #1 · answered by Anonymous · 0⤊ 1⤋
As you can see this is a REDOX reaction:
2 K2Cr2O7 + 3 C2H6O + 8 H2SO4 >>> 2 Cr2(SO4)3 + 2 K2SO4 + 3 C2H4O2 + 11 H2O
(Chromium 6+ ----> Chromium 3+
Carbon 2- -------> Carbon 0)
You balance the semirreactions and after that, you can complete the rest of coefficients.
Hope it helps!
2007-03-28 08:12:20 · answer #2 · answered by CHESSLARUS 7 · 0⤊ 1⤋
2K2CrO7 +2C2H6O +5H2SO4--->Cr2(SO4)3 +2K2SO4 +2C2H4O2 +11H2O
I have balanced the K, the Cr, the SO4, the C,
The H and O do not balance.
Are the products correct?
.
2007-03-28 09:04:02 · answer #3 · answered by science teacher 7 · 0⤊ 0⤋