Tickets for a high school dance cost $1 each if purchased in advance of the dance, but are $1.50 each if bought at the door. If 100 tickets were sold and $120 was collected, how many tickets were sold in advance and how many were sold at the door?
2007-03-28 07:47:44 · 5 answers · asked by aviator 5 in Education & Reference ➔ Homework Help
x=number of tickets sold in advance
y=number of tickets sold at the door
x+y=100 tickets
y=100-x
1.00x + 1.50y = $120
Substitute in your value for y from above so you are working with all x values
1.00x + 1.50(100-x) = $120
1x + 150-1.5x = 120
Keep solving and you will find your value for x. When you have that, you can find out y (tickets at the door), with y=100-x.
I don't want to do all the work for you, but hopefully this helps.
2007-03-28 08:07:27 · answer #1 · answered by MissD 2 · 0⤊ 1⤋
Let 'x' tickets be sold in advance and 'y' tickets at the door.
Since 100 tickets were sold,
x + y = 100
or, y = 100 - x ..............(i)
Earnings from tickets sold in advance = $ x
Earnings from tickets sold at door = $ 1.5y
Therefore,
total earnings = $ x + $ 1.5 y = $ 120
but from (i),
x + 1.5(100 - x) = 120
or, x + 150 - 1.5x = 120
or, -0.5x = 120 - 150
or, -0.5x = -30
or, x = -30/-0.5
or x = 60
y = 100 - x
or y = 100 - 60
or y =40
ANS: 60 tickets were sold in advance and 40 tickets were sold at the door.
2007-03-28 15:00:56 · answer #2 · answered by Periscope 2 · 0⤊ 1⤋
60 were sold before and 40 were sold at the door.
60*$1.00=$60 in advance
40*$1.50=$60 at the door.
total $120!
2007-03-28 14:55:39 · answer #3 · answered by boopi 2 · 0⤊ 1⤋
60 tix at 1.00 = 60.00 and 40 tix at 1.50 =60
60.00+60.00=120
60+40=100 tix
2007-03-28 15:00:26 · answer #4 · answered by Anonymous · 0⤊ 1⤋
80. 120 divided by 1.50. i might be wrong though.
2007-03-28 14:54:11 · answer #5 · answered by Chantel J 3 · 0⤊ 1⤋