Mike Rode his bike from home to Smallvill at 20mph And then walked back home at 5mph.The total round trip took him 10 hours.What is the distance from Home to Smallvil?
2007-03-28 05:13:12 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
it would be y=x(20*10)+z(5*10) where y would be the answer, x would be the time he rode his bike, and z would be the time he walked.
dont advertise on this site please (to the first guy who answered)
2007-03-28 05:20:40 · answer #1 · answered by vishalb777 3 · 0⤊ 0⤋
Let the time taken for Mike to go from home to smallville be x and the time taken to go back to his home be 10-x.
Therefore,
Distance= speed * time
So,
20x=5(10-x)
20x=50-5x
20x+5x=50
25x=50
x=2
Therefore, the distance from his home to smallville= 20x=20*2=40 km
2007-03-28 13:07:35 · answer #2 · answered by Bubblez 3 · 0⤊ 0⤋
t1 in bike t1=Distance/20
t2 by walk t2=Distance/5
t1+t2=10hours
5:20 = 1:4
2+8 = 10 hours ie 2 hours in bike and 8 hours by walk.
So distance is 8*5=40miles or 2*20=40 miles
Converse, 40miles in 20mph takes 2 hours.
Then 40miles in 5mph takes 8 hours. Total 2+8=10.
So 40miles is the disatnce from Home to Smallvil.
Why he left his bike?(Just for fun)
2007-03-28 12:23:16 · answer #3 · answered by prakash k 1 · 0⤊ 0⤋
x/20 +x/5 = 10
x +4X = 200
5x = 200
x=40 distance
verify
40/20 + 40/5 = 10
2+8 = 10
2007-03-28 12:20:37 · answer #4 · answered by Grant d 4 · 0⤊ 0⤋