Yes you use algebra
Train A distance from london = 100 * t
Train B distance from London = 500 - 80 * t
When do these equal each other?
100t = 500 - 80t
180t = 500
t = 2.77 hours
2007-03-28 04:58:49
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answer #1
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answered by Robin the Electrocuted 5
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the trick is that when both train meet, no matter what their speed was, they would have spent the same time t from the moment of departure till they meet and the distances they have travelled would sum up to the distance between L and G
London train will have traveled 100t miles and Glasgow train will have traveled 80t miles when they meet.
So, 100t + 80t = S ( distance between L and G)
given S, you will get t and 12:00 + t will get you the time.
2007-03-28 12:06:41
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answer #2
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answered by ArcticOwl 1
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Deduct 180 miles(London,100mph+Glasgow, 80 mph) from the actual distance for every hour traveled until it is zero. The hour at which distance is zero, is the hour the two trains meet.
2007-03-28 12:25:50
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answer #3
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answered by Bubblez 3
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Another way of looking at is that they have to cover 500 miles of track between them and their combined speed is 180mph, so the time for them to collide (ie when they have covered all the track!) is 500/180 = 2 and 7/9 hours.
No algebra needed.
2007-03-28 12:46:18
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answer #4
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answered by Martin 5
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let Sg=distance tavelled
by train from glasgow
=80*t
let Sl=distance travelled
by train from london
=100*t
let x= Sg+Sl
=distance between glasgow
and london
therefore,
x=80t+100t
=180t
hence,t= (x/180) hours
Sg=(4/9)*t (distance from G)
Sl = (5/9)*t (distance from L)
you now have the positions!
distance in miles
i hope that this helps
2007-03-28 15:25:44
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answer #5
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answered by Anonymous
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However, if one was a Pendolino and the other a Thames Train you may not wish them to meet.
2007-03-28 12:06:15
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answer #6
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answered by Anonymous
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I always thought the question was "Which train is closer to London when they pass?"
Did I miss something?
2007-03-28 12:05:00
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answer #7
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answered by Pit Bull 5
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Distance = (velocity)*(time travelled)
Distance between towns = TD
TD = D1 + D2 = (V1)(time1) + (V2)(time2)
Use these basic sets of equations, plug in known times and velocities to find distances, or plug in velocities and distances to find times.
2007-03-28 11:58:39
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answer #8
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answered by MamaMia © 7
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Yes use algebra it works wonders!
2007-03-28 14:19:46
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answer #9
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answered by Anonymous
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