im 19 years old and very confused I like girls and find them sexualiy attractive but i also like looking at men to in a non sexual way ie checking them out etc am i normal or am i a bisexual or what thanks
2007-03-28 04:51:28 · 6 answers · asked by tBAgmonster 3 in Society & Culture ➔ Cultures & Groups ➔ Lesbian, Gay, Bisexual, and Transgender
I know a lot of straight dudes who "check out " guys. It's quite common.
2007-03-28 05:00:39 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Don't be confused, if you also have a sexual attraction to members of the same sex, you're in all probability a bisexual. Accept your sexuality, rather than fight it. And to those who might look down on the way you are, show them the birdie.
2007-03-28 13:09:42 · answer #2 · answered by Gaymes Last Orchestra 6 · 0⤊ 0⤋
I'd say that if you don't look at men in a sexual way then you are just normal. Everyone can appreciate a good looking person no matter what their sex is. Its natural to check everyone out. Don't be worried.
2007-03-28 11:55:29 · answer #3 · answered by Justin 2 · 0⤊ 0⤋
At the tender age of 19, things are going to start making sense soon enough. If you simply like looking at men, aren't aroused by them in any sense whatsoever and cannot see yourself in a relationship with a man, perhaps you are a lesbian. Unfortunately, we can't answer that for you, it's something that you have to discover for yourself! Best of luck!
2007-03-29 05:25:59 · answer #4 · answered by Zarathustra 4 · 0⤊ 0⤋
i've been out as a lesbian since i was 14. you are totally normal. i check out men all the time, and my straight friends say "how would you know?"..but i can appreciate a good/great looking man, i just want to sleep with him...
they are still nice to look at!!
2007-03-28 12:10:32 · answer #5 · answered by Taken by a Texan 6 · 0⤊ 0⤋
you could be bisexual or just confused, give it some time and then you will know for sure.don't listen to other's putting you down, follow your own thoughts and desires.
2007-03-28 11:55:46 · answer #6 · answered by Cindy 2 · 0⤊ 0⤋