Please help me solve this?

Question

4x+y=4
3x-y=3

Answer 1

these are called linear equations in two variables or simultaneous equations

4x+y=4 .........(1)
3x-y=3 .........(2)

add equations (1) and (2)

4x+y + 3x - y=4+3
=>7x=7
=>x=1

substitute x=1 in equation (1)
=>4(1)+y=4
=>4+y=4
=>y=4-4=0

so x=1 and y=0

Answer 2

You can find the intersection point of these two lines by different methods, but the easiest one for this problem is called elimination. It means that you want to get rid of one of the variables by adding or subtracting the two equations.

Notice that in the top equation, you have a +y and in the bottom you have -y. Since these are opposite, if you add them together they will cancel each other out.

Add the two equations just like any other adding problem, by lining up the common terms, x's over x's, y's over y's, = over =. Then add striaght up and down.

4x+y=4
3x-y=3

7x = 7

Solve this equation for x by dividing both sides by 7, to "undo" the 7 times x on the left side. Then you will find that x = 1.

Now that you have one of the variables, simply substitute that value into one of the original equations.

4x + y = 4
4(1) + y = 4
4 + y = 4

Subtract 4 from each side to get rid of the 4 on the left.

4 + y = 4
-4 -4
y = 0

So your answers are x = 1 and y = 0. So the coordinates of the point where those 2 lines cross is (1,0).

Answer 3

4x + y = 4
3x - y = 3

I think the easiest way is eliminated them!

First, make the x or y coeficient same! in this problem, i same the y coeficient

4x + y = 4
3x - y = 3

then annihilate the y

4x+y = 4
3x-y = 3
-----------+ (in this prob, we use +, because 1y+(-1y)=0)
7x = 7
x = 1

then substitue the x into the linier system, up to you to use which system

4x+y=4
4(1)+y=4
4+y=4
y=0

or

3x-y=3
3(1)-y=3
3-y=3
y=0

And the solving is {x,y | x = 1, and y =0}

Answer 4

4x +3x +y -y = 4 +3

7x = 7

x = 1

4×1 +y = 4

4 +y = 4

y = 0

Answer 5

4x + y = 4
3x - y = 3

Add the equations together and you get:

7x = 7
x = 1

Go back and substitute x in either equation:

4(1) + y = 4
y = 0

Answer 6

First solve one of the equatons for y:
y=4-4x

Then substitute this value for y into the other equation:
3x-(4-4x)=3
3x-4+4x=3
7x=7
x=1

Then solve for y:
y=4-4x1
y=0

Answer 7

4x+y=4 -------(1)=> y=4-4x put this in (2)
3x-y=3 --------(2)

3x-4+4x=3 => 7x=7 => x=1 put this in (1) => y=0.