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In a centrifuge, an astronaut experiences a centripetal acceleration of 6g’s (that is 6*9.8m/s/s). If the astronaut is located 15 meters from the axis, what is the centrifuge’s angular velocity (rads/sec)? What is the astronaut’s linear velocity?

2007-03-28 03:44:36 · 2 answers · asked by GSU 1 in Science & Mathematics Physics

2 answers

6g = a = V²/R = ω²R

V = √(aR) = 29.7 m/s
ω = √(a/R) = 1.98 1/s

2007-03-28 05:16:57 · answer #1 · answered by Alexander 6 · 0 0

it rather is "clean up" no longer "slove" please. thank you. Use ability concerns. Get the finished ability ability loss for falling 2 metres. it could have a translational velocity V on the backside. yet V is likewise the cost of the rim of the disc that's radius x omega. it rather is omega, the angular velocity on the backside, you gotta locate. entire ok.e. gained is translational (one million/2-M-V^2) plus rotational (one million/2-MI-omega^2) Equate entire loss in p.e. to entire benefit in ok.e. to artwork out the cost of omega. (Mass of the disc cancels interior the equation.) Now why could they want the 2nd of inertia on the tip of the question while the mass and radius are already worry-free?

2017-01-05 08:24:21 · answer #2 · answered by ? 4 · 0 0

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