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assume that A is a square matrix that satisfies A^2 - 7A + I = 0.

how do i show that A^-1 = 7I - A ??

2007-03-28 03:27:13 · 1 answers · asked by Chicken Feet 1 in Science & Mathematics Mathematics

1 answers

Multiply your original equation by A^-1
and remember that A * A^-1 = A^-1 * A = I, the identity matrix.

2007-03-28 03:37:19 · answer #1 · answered by Quadrillerator 5 · 0 0

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