One gear wheel turns another, the tenth being on the rims. The wheels have 40-cm and 50cmm radii, and the smaller wheel rotates at 20rpm. Find the angular speed of the larger wheel, in radians per second.
2007-03-28 02:50:00 · 3 answers · asked by Sophia D 1 in Science & Mathematics ➔ Mathematics
For every one revolution of the smaller wheel, the larger wheel makes 4/5 of a revolution.
The larger wheel thus rotates at (4/5) *20 = 16 rpm
1 revolution is equal to 2 pi radians
Thus the larger wheel is rotating at an angular speed of 32 pi
radians per minute
This is equal to (32/60) radians per second = 0.533333 radians per second
2007-03-28 03:01:49 · answer #1 · answered by z_o_r_r_o 6 · 0⤊ 0⤋
4/5 of 20 = 16 rpm
2007-03-28 09:54:15 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The last person made one little slip. They lost the pi near the end so it should be (32/60)*pi radians per sec.
This is approx. 1.676 rad.p.s.
2007-03-28 13:44:26 · answer #3 · answered by mathsmanretired 7 · 0⤊ 0⤋