More of a physics question:
X =Vot + 1/2at^2
100 = 1/2a*36
a = 100/18 = 50/9 m/sec^2
2007-03-28 01:49:20
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answer #1
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answered by blighmaster 3
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Vf: very final speed Vi: preliminary speed(0m/s) a: acceleration T: time (6.0s) Vf^2-Vi^2=2 x a x a hundred equation1 a million/2 x a x T^2 = a hundred equation 2 From equation 2, a =5.6 m/s^2 From equation a million, Vf = 33.3m/s
2016-12-08 13:02:25
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answer #2
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answered by ? 4
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You could use s=u*t+a/2*t^2 with t = 6 and s =100 and u=0
this rearranges to a=200/36 then v=u+at gives you v = 200/6 m/sec
2007-03-28 01:50:58
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answer #3
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answered by Anonymous
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Use the formula
S= 1/2 (u+v)t
2007-03-28 01:53:49
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answer #4
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answered by Anonymous
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let's see, you know d, t and Vo. You know that a is constant. and you want to know Vf
since you don't know "a", you need an equation of motion without "a".
how about this one...
d = 1/2 x ( Vf - Vo) x t
100 m = 1/2 x Vf x 6 sec
200 m / 6 sec = Vf
Vf = 33.33 m/s
2007-03-28 01:55:57
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answer #5
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answered by Dr W 7
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v = antiderivative of a
v = at + C(1)
x = antiderivative of v
x = (at^2) / 2 + C(1)*t + C(2)
Solve for the constants:
0 = a*0 + C(1)
C(1) = 0
0 = (a*(0)^2) / 2 + 0*t + C(2)
C(2) = 0
v = at
x = (at^2) / 2
100 = (a(6)^2) / 2
200 = 36a
a = 5.6 m/s
2007-03-28 03:06:00
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answer #6
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answered by Anonymous
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