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6 answers

More of a physics question:

X =Vot + 1/2at^2

100 = 1/2a*36

a = 100/18 = 50/9 m/sec^2

2007-03-28 01:49:20 · answer #1 · answered by blighmaster 3 · 0 1

Vf: very final speed Vi: preliminary speed(0m/s) a: acceleration T: time (6.0s) Vf^2-Vi^2=2 x a x a hundred equation1 a million/2 x a x T^2 = a hundred equation 2 From equation 2, a =5.6 m/s^2 From equation a million, Vf = 33.3m/s

2016-12-08 13:02:25 · answer #2 · answered by ? 4 · 0 0

You could use s=u*t+a/2*t^2 with t = 6 and s =100 and u=0
this rearranges to a=200/36 then v=u+at gives you v = 200/6 m/sec

2007-03-28 01:50:58 · answer #3 · answered by Anonymous · 0 0

Use the formula
S= 1/2 (u+v)t

2007-03-28 01:53:49 · answer #4 · answered by Anonymous · 0 1

let's see, you know d, t and Vo. You know that a is constant. and you want to know Vf

since you don't know "a", you need an equation of motion without "a".

how about this one...

d = 1/2 x ( Vf - Vo) x t
100 m = 1/2 x Vf x 6 sec
200 m / 6 sec = Vf

Vf = 33.33 m/s

2007-03-28 01:55:57 · answer #5 · answered by Dr W 7 · 1 0

v = antiderivative of a

v = at + C(1)


x = antiderivative of v

x = (at^2) / 2 + C(1)*t + C(2)

Solve for the constants:

0 = a*0 + C(1)
C(1) = 0

0 = (a*(0)^2) / 2 + 0*t + C(2)
C(2) = 0

v = at
x = (at^2) / 2

100 = (a(6)^2) / 2
200 = 36a
a = 5.6 m/s

2007-03-28 03:06:00 · answer #6 · answered by Anonymous · 0 2

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