while(i<=j && j<=i && i!=j ) {} for what values of i and j will this loop be infinity?

Answer 1

i=2
j=--j=1

Answer 2

It depends on what programming language this is, and what types i and j are. I think in C, C++ and Java, the loop condition will always be false. Unless you have some Machiavellian programmer who's #defined i and j to be expressions with side effects. Or if you are not using one of the familiar languages, but instead you are using a language that defines "i!" as "i factorial" and i == 2, j == 2.

Answer 3

The reason to this equation multiplication and division of the attribution of the Houston Space station and getting the polarity of the atmosphere and the satiable need to be followed to the depth of the incarnation and the rehabilation of multiplication and the complexity of the situation

Answer 4

The loop can run only for a finite time. Because the conditions are really strange and are very opposite to one another.

If there is a answer let me know it([e-mail]).

Answer 5

There are no values where you can satisfy the three conditions. Because the first two can only be true if i and j are equal ... and which makes the third one false.

Answer 6

let me explain with this with a factor "height"

Think if the below is possible,

I should be smaller or equal to your's height
You should be smaller or equal to the height of mine
We both donnt have equal height.

Not at all possible.

=>No values exist for i and j for the above conditions.