what is dy/dx of 14-(16/(3+x))?

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2007-03-27 22:54:54 · 4 answers · asked by Gatlas 3 in Science & Mathematics ➔ Mathematics

dy/dx {14-[16/(3+x)]}

=0-(-1)(16)(3+x)^-2

=16/(3+x)^2 (solved)

hope you can understand :)

2007-03-28 01:11:05 · answer #1 · answered by ahyeh85 1 · 0⤊ 0⤋

y = 14 - 16.(3 + x)^(-1)
dy/dx = 16.(3 + x)^(-2) = 16/(3 + x)Â²

2007-03-28 06:38:08 · answer #2 · answered by Como 7 · 0⤊ 0⤋

d/dx(14- 16/(3+x)
= d/dx(14) - 16d/dx(1/3+x)

= -16 *2 *(3+x)^-2

= -32/(x+3)^2

2007-03-28 06:00:26 · answer #3 · answered by Mein Hoon Na 7 · 0⤊ 1⤋

(16)/(3+x)^2

2007-03-28 06:09:39 · answer #4 · answered by jsb 2 · 1⤊ 0⤋