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3 answers

the perimeter will also double its size; that is because all sides have been doubled

2007-03-27 23:33:54 · answer #1 · answered by The Pretender 2 · 0 0

if you double the height everything doubles, so the perimeter would double. I can't see how you can double height and the two bases and not double sides to accomadte the bigger shape. So factor on perimeter should be it doubles, so 2. Now when you double the amounts as so the area however factors 4, on an area = 1/2 h(a+ b) and h = 5 and a = 6 and b = 12 doubles gives you 1/2 10(12 + 24) gives you 5(36) = 180 originally you get 1/2 5(18) = 45 so that quadruples on the area, perimeter doubles. If you triple all amounts I say perimeter stays true and triples and area would then go 3 x 3 and 9 times 45 = 405. questions email me m_lavallee@cox.net

2007-03-28 06:22:21 · answer #2 · answered by niceguyswthrt 2 · 0 0

Assuming it is an Iscoceles trapezoid,

P(perimeter) = B+b+sqt(h^2 + ((B-b)/2)^2) =

= B+b+(1/2)sqt(4h^2 + (B-b)^2)

P2 = 2B+2b + (1/2)sqt(4(2h)^2 + (2(B-b))^2) =

2(B+b) + (1/2)sqt(16h^2 + 4(B-b)^2) =

= 2(B +b) +sqt(4h^2 + (B - b)^2)

In other words, perimeter has doubled

2007-03-28 06:20:09 · answer #3 · answered by blighmaster 3 · 0 0

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