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I have some muriatic acid, which is 30 per cent v/v HCl. What is a simple calculation to determine how much water to add to a particular volume of the muriatic acid to dilute it to other strengths? The calculation must be usable for any starting percentage and any desired percentage.

2007-03-27 16:10:34 · 3 answers · asked by David A 5 in Science & Mathematics Chemistry

3 answers

Very simple, it's C1V1=C2V2, where
C1=concentration of the starting solution
V1= volume of the starting solution
C2=concentration that you want to end up with
V2=colume that you want to end up with

Good Luck!

2007-03-27 16:17:25 · answer #1 · answered by Anonymous · 0 0

As you have got 30% v/v HCl and say You want to get 10% HCl,then proceed as follows:
3 0% HCl * volume say X = 10% HCl * volume say 100 mll;

or Volume of 30% HCL = 10*100/30 ml

or Volume of 30% HCL = 100/3 ml

or Volume of 30% HCL = 33.33 ml

Similarly other percentage of muriatic acid can be prepared.

2007-04-03 01:53:50 · answer #2 · answered by sb 7 · 0 0

I always like

Volume1 X Concentration1 = Volume2 X Concentration2

2007-03-27 16:19:20 · answer #3 · answered by BP 7 · 0 0

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